Web Reference: Given a non-negative int n, compute recursively (no loops) the count of the occurrences of 8 as a digit, except that an 8 with another 8 immediately to its left counts double, so 8818 yields 4. Note that mod (%) by 10 yields the rightmost digit (126 % 10 is 6), while divide (/) by 10 removes the rightmost digit (126 / 10 is 12). What's Related? Solutions to CodingBat problems. Contribute to mirandaio/codingbat development by creating an account on GitHub. Recursion - 1 (powerN) Java Solution || Codingbat.com Records In Java - Full Tutorial - The Best New Java Feature You're Not Using
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