Web Reference: Given a non-negative int n, compute recursively (no loops) the count of the occurrences of 8 as a digit, except that an 8 with another 8 immediately to its left counts double, so 8818 yields 4. Note that mod (%) by 10 yields the rightmost digit (126 % 10 is 6), while divide (/) by 10 removes the rightmost digit (126 / 10 is 12). What's Related? Recursion strategy: first test for one or two base cases that are so simple, the answer can be returned immediately. Otherwise, make a recursive a call for a smaller case (that is, a case which is a step towards the base case). Solutions to CodingBat problems. Contribute to mirandaio/codingbat development by creating an account on GitHub.
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