Web Reference: Solution for the Playlist problem from Sorting & Searching in CSES. We need to find the longest “valid” window where validity means no repeated elements. Think of this like a caterpillar crawling along the array. The caterpillar’s body represents our current window. When we see a new unique song, we extend the front. When we see a duplicate, we shrink from the back until the duplicate is removed. Jul 23, 2025 · Maintain two pointers, start = 0 and end = 0 to mark the starting and ending point of window. Also maintain a map, say mp to store the last index of each character. If the character at index = end is not present in the map, we insert the character along with the current index.
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